How to calculate IP address from subnet mask?

What is a 192.168 0.1 subnet mask?

A subnet mask is used to define the range of addresses in an address space. This is particularly useful for defining the subnet on a single IP address, usually referred to as the local IP address. This address is often learned by running a ping command. A subnet mask can be used to define whether a particular IP address is in the same subnet as another address.

The subnet mask is represented by a bit string, with the length of this string set according to the number of address bits desired. Most modern chips and operating systems have default subnet masks that are not modified unless required. For example, Local Area Network (LAN) subnets use a /24 network mask, meaning that each byte of the IP address has 24 binary zeros or ones. This type of subnet mask is typically used on non-routable IP addresses.

The local IP network address is often defined by the best route that is available to the system. If there is only one route between the source and destination IP addresses, the subnet mask for the local IP address will be defined by the last part of the IP address. For example, the following IP address shows a local IP address of 192.168.100.13:

In an enterprise environment, the subnets can be defined to provide access to a workgroup, organization, department, laboratory, branch office, data center, or similar group. If you have two machines that need to communicate, and the best route between them is east-west, then the east-west route is the preferred route for routing between them. Therefore, the subnet mask should be defined to show that the mask is east-west. The netmask should be 255.224

128

240

A subnet mask of 192.128/22 will allow communication between any two IP addresses in the 192.0/22 network.

The above example shows that a subnet mask of 255.224 can be used to define a subnet mask of 192. It would allow communication between any two addresses in that network.

What is the subnet mask for 192.168 0.0 24?

There are 8 bits after the "0." That's part of the address. The first 24 bits are the subnet address. This contains the IP address that has not been split out into any other network segment/broadcast/subnet.
255.128 239. = 10.15.1
Edit: I think I may need a few more diagrams to describe it. Since the initial "0." is not part of the address, we start with 100 0xFF 24. 0x0 16. 0xFF 8. 0x0 0. Then the bits are shifted left () by total number of bits (24 bits) - 1 spaces. 100 0000 0000 0000 0000 1111. 0000 0001 0000 0000 0000. 100 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1001. 0000 0000 0000 0000 0000 0000 0000 0000 0001 0000 0000 0000 0000. 0000 0000 0000 0000 0000 0000 0001 0000 0000 0000 0000 0000 0000 0000. Subtract 1 from the 24 bits is 23. Add 23 to the 16 bits is 3. Add 1. Add 6 to the 8 bits is 6. Subtract 6 from 24 is 18.

If we start at 12 (total number of bits is 23), then the final result is 18. Only 18 is left. So 24 - 18 is 6. Then if we start at 11 (total number of bits is 22), then the final result is 2.